Mysql 查询语句怎么写？

[xiyangyang]

开发市场调查业务，有一个调查问题表responses （一百万行), 是市场调查的原始数据，包含survey_id(调查表的类型列)，response_no(被调查者列)，interview_date(调查日期)， question_label（问题列）, value（回答列）, section_unique_id（部门列)等。
每一行对应某个被调查者回答的一个问题和它的调查结果。一个被调查者一次会回答30个问题，所以会产生30行。
另有一个计算公式表 (40行）, 是对调查结果的分析计算公式，这些公式都是sql语句。
根据计算公式，产生一个结果表results。
现在的问题是,要设计一些sql语句，调查有多少人的回答是类似如下这样的组合：
1. 回答问题Q1,答案是1或8或9
并且
2. 回答问题Q2,答案是1或8或9
并且
。。。。。。
最好能用group by section。

比如如下这个例子：
计算公式的说明是这样。
((Q2A = 1 OR Q2A = 8 OR Q2A = 9) AND (Q2B = 1 OR Q2B = 8 OR Q2B = 9) AND (Q2C = 1 OR Q2C = 8 OR Q2C = 9) AND (Q2D = 1 OR Q2D = 8 OR Q2D = 9) AND (Q2E = 1 OR Q2E = 8 OR Q2E = 9) AND (Q2F = 1 OR Q2F = 8 OR Q2F = 9) AND (Q2G = 1 OR Q2G = 8 OR Q2G = 9) AND (Q2H = 1 OR Q2H = 8 OR Q2H = 9) AND (Q2I = 1 OR Q2I = 8 OR Q2I = 9) AND (Q5 = 1 OR Q5 = 8 OR Q5 = 9) AND (Q6 = 1 OR Q6 = 8 OR Q6 = 9))

我现在写了这样一个mysql语句：

SELECT section_unique_id as "section_unique_id", COUNT(*) as "hit" FROM responses WHERE
question_label = "Q2A" AND value IN (1,8,9)
AND
 (response_no, survey_id, interview_date) IN (SELECT DISTINCT response_no, survey_id, interview_date FROM responses WHERE question_label = "Q2B" AND value IN (1,8,9))
AND
 (response_no, survey_id, interview_date) IN (SELECT DISTINCT response_no, survey_id, interview_date FROM responses WHERE question_label = "Q2C" AND  value IN (1,8,9))
AND
 (response_no, survey_id, interview_date) IN (SELECT DISTINCT response_no, survey_id, interview_date FROM responses WHERE question_label = "Q2D" AND value IN (1,8,9))
AND
 (response_no, survey_id, interview_date) IN (SELECT DISTINCT response_no, survey_id, interview_date FROM responses WHERE question_label = "Q2E" AND value IN (1,8,9))
 AND
 (response_no, survey_id, interview_date) IN (SELECT DISTINCT response_no, survey_id, interview_date FROM responses WHERE question_label = "Q2F" AND value IN (1,8,9))
 AND
 (response_no, survey_id, interview_date) IN (SELECT DISTINCT response_no, survey_id, interview_date FROM responses WHERE question_label = "Q2G" AND value IN (1,8,9))
 AND
 (response_no, survey_id, interview_date) IN (SELECT DISTINCT response_no, survey_id, interview_date FROM responses WHERE question_label = "Q2H" AND value IN (1,8,9))
 AND
 (response_no, survey_id, interview_date) IN (SELECT DISTINCT response_no, survey_id, interview_date FROM responses WHERE question_label = "Q2I" AND value IN (1,8,9))
 AND
 (response_no, survey_id, interview_date) IN (SELECT DISTINCT response_no, survey_id, interview_date FROM responses WHERE question_label = "Q5" AND value IN (1,8,9))
 AND
 (response_no, survey_id, interview_date) IN (SELECT DISTINCT response_no, survey_id, interview_date FROM responses WHERE question_label = "Q6" AND value IN (1,8,9))

结果，运行一次，用了12秒，太慢了。
请教mysql高手，有没有办法能加快计算速度。

[cye3s]

那么多子查询，快就怪了，先用sum(case...l
)语句转横表,就是每人一行记录，包含所有问题回答，试试

[xiyangyang]

对mysql不熟悉，但是要求比较急，可否请大侠写这个sql语句？谢谢了。

[airylinus]

最简单的加速方法是用视图，怎么用查 MySQL 文档。
另外，还可以把每个问题的答案转换成二进制，用二进制运算替代子查询。

[tranch]

SELECT section_unique_id AS "section_unique_id",
COUNT(*) AS "hit"
FROM responses
WHERE (response_no,
survey_id,
interview_date) IN
(SELECT DISTINCT response_no,
survey_id,
interview_date
FROM responses
WHERE question_label IN ("Q2A", "Q2B", "Q2C", "Q2B", "Q2D", "Q2E", "Q2F", "Q2G", "Q2H", "Q2I", "Q5", "Q6")
AND value IN (1, 8, 9))

[xiyangyang]

tranch:
我们想要的是，知道有多少个这样的被调查者，他回答的问题满足这样的条件：Q2A in (1,8,9) 并且Q2B in (1,8,9), .....
所以，question_label IN ("Q2A", "Q2B", 。。。。。。)， 这样是不对的

airylinus:
每个问题的答案都是1到10的整数，没法转换成二进制，因为其他的计算公式还需要他们呢。

[tranch]

建议把以上问题贴到问答网站（比如 segmentfault.com）上去讨论，这里不适合发代码。

[mringg]

用子查询速度肯定慢