召集爱看小薄本子又熟悉 regex 的各路绅士大神~

[eromoe]

大家都知道，小薄本子多了，整理起来就麻烦了=。=
我想按作者分，按社团分，按展会分等等，所以写了个正则 想从一个本子的名字里抽取所有信息
但是本子标题五花八门，如下
0. (event ) (tag ) [group (artist )] title (form ) [addition1] [addition2]

1. (event ) [group (artist )] title (form ) [addition1]

2. [event] [group (artist )] title (form ) (addition1 )

3. (tag ) [group (artist )] title

4. [group (artist )] title

5. title

我试着写了一个

import re
regex_patern = ur'([\(\[](?P<event>[^\)\]]*)[\)\]])?\s*([\(\[](?P<type>[^\)\](\)\])]*)[\)\]])?\s*(\[(?P<group>[^\(\]]*)(\((?P<artist>[^\)]*)\))?\])?(?P<title>[^\(\)\[\]]*)([\(\[](?P<from>[^\)\]]*)[\)\]])?(\s*[\(\[](?P<more1>[^\)\]]*)[\)\]])'

p = re.compile (regex_patern )

rows= [
'(event ) (tag ) [group (artist )] title (form ) [addition1] [addition2]',
'(event ) [group (artist )] title (form ) [addition1]',
'[event] [group (artist )] title (form ) (addition1 )',
'(tag ) [group (artist )] title',
'[group (artist )] title',
'title',
]

for r in rows:
    r = re.search (p, r )
    print r.groupdict ()

#输出：

{u'from': 'form', u'more1': 'addition1', u'artist': 'artist', u'title': ' title ', u'group': 'group ', u'type': 'tag', u'event': 'event'}
{u'from': 'form', u'more1': 'addition1', u'artist': 'artist', u'title': ' title ', u'group': 'group ', u'type': None, u'event': 'event'}
{u'from': 'form', u'more1': 'addition1', u'artist': 'artist', u'title': ' title ', u'group': 'group ', u'type': None, u'event': 'event'}
{u'from': None, u'more1': 'group (artist', u'artist': None, u'title': '', u'group': None, u'type': None, u'event': 'tag'}
{u'from': None, u'more1': 'group (artist', u'artist': None, u'title': '', u'group': None, u'type': None, u'event': None}
---------------------------------------------------------------------------
AttributeError                            Traceback (most recent call last )
<ipython-input-5-831c548bc3f0> in <module>()
     15 for r in rows:
     16     r = re.search (p, r )
---> 17     print r.groupdict ()

AttributeError: 'NoneType' object has no attribute 'groupdict'

从第四行开始结果就不对了，我感觉 re 应该要先匹配中间的简单规则，再最后扩展到最复杂的规则，
但是不知道怎么写。。。。特来请教各位

[plqws]

为啥一定要用正则，代码看起来好难改的样子。
还有我觉得这种东西用 日文分词 + tag 整理起来更方便吧。

[rogerchen]

(\s*[\(\[](?P<more1>[^\)\]]*)[\)\]]) 最后一个空白为什么要捕捉，和前边不一致，而且 more1 这个段是可选的吧，应该只有 title 这个段是强制的

[rogerchen]

楼主我还发现一个问题，你来源一会写 from 一会儿写 form ，虽然不影响吧，但确实把我看晕了

[rogerchen]

改了之后是这样，貌似还有点小问题，我继续看
$ python re.py
{u'from': 'form ', u'more1': 'addition1', u'artist': 'artist ', u'title': ' title ', u'group': 'group ', u'type': 'tag ', u'event': 'event '}
{u'from': 'form ', u'more1': 'addition1', u'artist': 'artist ', u'title': ' title ', u'group': 'group ', u'type': None, u'event': 'event '}
{u'from': 'form ', u'more1': 'addition1 ', u'artist': 'artist ', u'title': ' title ', u'group': 'group ', u'type': None, u'event': 'event'}
{u'from': None, u'more1': None, u'artist': 'artist ', u'title': ' title', u'group': 'group ', u'type': None, u'event': 'tag '}
{u'from': None, u'more1': None, u'artist': None, u'title': '', u'group': None, u'type': None, u'event': 'group (artist '}
{u'from': None, u'more1': None, u'artist': None, u'title': 'title', u'group': None, u'type': None, u'event': None}

[rogerchen]

import re
regex_patern = ur'([\(\[](?P<event>[^\()\)\]]*)[\)\]])?\s*([\(\[](?P<type>[^\)\](\)\])]*)[\)\]])?\s*(\[(?P<group>[^\(\]]*)(\((?P<artist>[^\)]*)\))?\])?(?P<title>[^\(\)\[\]]*)([\(\[](?P<from>[^\)\]]*)[\)\]])?\s*([\(\[](?P<more1>[^\)\]]*)[\)\]])?'

p = re.compile (regex_patern )

rows= [
'(event ) (tag ) [group (artist )] title (form ) [addition1] [addition2]',
'(event ) [group (artist )] title (form ) [addition1]',
'[event] [group (artist )] title (form ) (addition1 )',
'(tag ) [group (artist )] title',
'[group (artist )] title',
'title',
]

for r in rows:
r = re.search (p, r )
print r.groupdict ()

完全改好了，你有两个地方不对，一个是最后边那个地方强制捕获了，一个是不能让 event 捕获 [group (artist )]，所以在 event 那个段里边要改成最后\(也放弃。

$ python re.py
{u'from': 'form ', u'more1': 'addition1', u'artist': 'artist ', u'title': ' title ', u'group': 'group ', u'type': 'tag ', u'event': 'event '}
{u'from': 'form ', u'more1': 'addition1', u'artist': 'artist ', u'title': ' title ', u'group': 'group ', u'type': None, u'event': 'event '}
{u'from': 'form ', u'more1': 'addition1 ', u'artist': 'artist ', u'title': ' title ', u'group': 'group ', u'type': None, u'event': 'event'}
{u'from': None, u'more1': None, u'artist': 'artist ', u'title': ' title', u'group': 'group ', u'type': None, u'event': 'tag '}
{u'from': None, u'more1': None, u'artist': 'artist ', u'title': ' title', u'group': 'group ', u'type': None, u'event': None}
{u'from': None, u'more1': None, u'artist': None, u'title': 'title', u'group': None, u'type': None, u'event': None}

[eromoe]

@rogerchen 非常感谢，准备写点代码先测测分类效果~

[eromoe]

突然发现一个很囧的问题。。。
[event] [group] title (from )
[event] [artist] title (from )

是不是无解啊。。。
正则能不能写出 从 title 左边抓一个[XXX] ，然后 XXX 不包含 同人 /Cxx/成年 XXX 这样的，来判断是 group+artist 块？

[rogerchen]

都要涉及到比较字符串了，只用正则搞就是黑魔法了，建议先抓出来再写点代码判断

[eromoe]

@rogerchen 嗯，也只能这样了