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timshi
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datastore query 问题

  •  
  •   timshi · 2010-12-10 06:56:06 +08:00 · 4918 次点击
    这是一个创建于 5099 天前的主题,其中的信息可能已经有所发展或是发生改变。
    假设我有这样一个 model

    class Person{
    @Persistent
    private List<Category> tags = ArrayList<Category>()
    }

    I want to let the user query a person based on his/her tag, so I had my query filter like this:

    tags.contains(tagValue1)

    and if the user want to search for multiple tags, I would just add to the filter so if the user is searching for 3 tags, then the query would be

    tags.contains(tagValue1) && tags.contains(tagValue2) && tags.contains(tagValue3)

    I think this approach is wrong, because the datastore then needs to have an index that have the tags property three times... and if the user search for more than 3 tags at a time then it will be broken.

    What's the proper way to do this? Do you guys have any suggestions?
    6 条回复    1970-01-01 08:00:00 +08:00
    MarkFull
        1
    MarkFull  
       2010-12-10 09:06:43 +08:00
    这个是3个queries吧
    timshi
        2
    timshi  
    OP
       2010-12-10 11:44:05 +08:00
    你是说我必须做3个query然后再intersect the result myself?
    MarkFull
        3
    MarkFull  
       2010-12-10 11:55:09 +08:00
    intersect是下策,built-in的GQL我不是很熟悉
    timshi
        4
    timshi  
    OP
       2010-12-10 12:43:49 +08:00
    那你会怎么做? 我本来以为这个个index应该是这样的

    person1, tagValue1
    person1, tagValue2
    person1, tagValue3

    i.e an additional for each value in the multi-value property, and GAE should do a merge join to get me the result.

    But my index file looks like this

    <datastore-index kind="Person" ancestor="false" source="auto">
    <property name="tags" direction="asc"/>
    <property name="tags" direction="asc"/>
    <property name="tags" direction="asc"/>
    <property name="tags" direction="asc"/>
    .....
    MarkFull
        5
    MarkFull  
       2010-12-10 12:58:25 +08:00
    no, each property should specify once for the same kind (Person).
    There should be only one line of <property name="tags" direction="asc"/>

    This is the GQL format you can reference:
    SELECT [* | __key__] FROM <kind>
    [WHERE <condition> [AND <condition> ...]]
    [ORDER BY <property> [ASC | DESC] [, <property> [ASC | DESC] ...]]
    [LIMIT [<offset>,]<count>]
    [OFFSET <offset>]

    <condition> := <property> {< | <= | > | >= | = | != } <value>
    <condition> := <property> IN <list>
    <condition> := ANCESTOR IS <entity or key>
    MarkFull
        6
    MarkFull  
       2010-12-10 13:01:30 +08:00
    Instead of using GQL, maybe you can use this:

    filter(property_operator, value)
    Adds a property condition filter to the query. Only entities with properties that meet all of the conditions will be returned by the query.
    Arguments:
    property_operator
    A string containing the property name, and an optional comparison operator. The name and the operator must be separated by a space, as in: age > The following comparison operators are supported: < <= = >= > != IN If the operator is omitted from the string (the argument is just the property name), the filter uses the = operator.
    value
    The value to use in the comparison on the right-hand side of the expression. Its type should be the value data type for the property being compared. See Types and Property Classes.
    query.filter('height >', 42).filter('city = ', 'Seattle')

    query.filter('user = ', users.get_current_user())

    from http://code.google.com/appengine/docs/python/datastore/queryclass.html#Query_filter
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