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Python 如何生成今天 0 点到现在的所有以小时为单位的时间字符串？ and ...
Eyon · 2020-09-02 19:23:29 +08:00 · 2090 次点击这是一个创建于 1538 天前的主题，其中的信息可能已经有所发展或是发生改变。
需求：
get_today = [2020090200,2020090201,2020090202...2020090219]
get_month=[2020090100,2020090101,2020090102......2020090219]
get_today = [2020090200,2020090201,2020090202...2020090219]
get_month=[2020090100,2020090101,2020090102......2020090219]
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Trim21 2020-09-02 19:29:41 +08:00 via Android
用 datetime （ 0 点）循环加 timedelta （ hours=1 ），直到大于当前时间，然后把符合条件的的序列化成你想要的格式
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Eyon OP @Trim21 谢谢
```python from datetime import datetime,timedelta now = datetime.now() thismonth_start = now.strftime('%Y%m01') start = datetime(2020,9,1) while True: if start < now: print(start.strftime('%Y%m%d%H')) start = start+timedelta(hours=1) ``` |
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3
tairan2006 2020-09-02 23:16:22 +08:00 via Android
zfill 函数了解一下
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4
TEwrc 2020-09-03 16:37:32 +08:00
@tairan2006 看了一下没太懂 请教一下怎么用到题主说的这个问题上呢？
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tairan2006 2020-09-03 17:31:25 +08:00
@TEwrc
now = datetime.now() prefix = now.strftime('%Y%m%d') return [prefix + str(x).zfill(2) for x in range(now.hour)] |
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TEwrc 2020-09-04 12:00:52 +08:00
@tairan2006 秒啊！感谢
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biglazycat 2020-09-11 23:03:28 +08:00
from datetime import datetime
time_list = [] now = datetime.now() start_day_hour = int(now.strftime('%Y%m%d00')) stop_day_hour = int(now.strftime('%Y%m%d%H')) for i in range(start_day_hour, stop_day_hour + 1): time_list.append(i) print(time_list) |
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