代码在 jupyternotebook 里写的,奇怪的是在办公室能用,家里不能用了... 整个功能就是用 apscheduler 定时运行生成随机数然后在 tkinter 里可视化 现在想保留原代码里 root.after 功能(因为直接用 root.after,按现在做法定时函数就没用了,因为 root.after 是循环的) 感觉可以用锁的方法,但是水平捉急写不出来,求指教。。
''' import datetime from apscheduler.schedulers.background import BackgroundScheduler import random import numpy as np from tkinter import * from tkinter import messagebox import matplotlib.pyplot as plt from matplotlib.backends.backend_tkagg import FigureCanvasTkAgg import multiprocessing from threading import Thread import time
root = Tk()
root.title("tkinter + Matplotlib")
root.geometry('700x750')
plt.rcParams['axes.unicode_minus']=False
plt.rcParams['font.sans-serif'] = ['SimHei']
fig = plt.figure()
ax1 = fig.add_subplot(1, 1, 1)
ax2 = ax1.twinx()
ax1.set_title('随机生成数')
ax1.set_ylim()
ax2.set_ylim()
ax1.set_xlim(0, 200)
ax2.set_xlim(0, 200)
ax1.grid(True)
ax1.set_xlabel("time")
ax1.set_ylabel("随机数 1")
ax2.set_ylabel("随机数 2")
canvas = FigureCanvasTkAgg(fig, master=root)
canvas.draw()
canvas.get_tk_widget().pack()
x = 0
ran1 = []
ran2 = []
times = []
def drawImg():
global ran1
global ran2
global times
global x
global ax1
global ax2
v1 = float(random.randint(-5, 5))
r1 = float(random.randint(-10, 10))
ran1.append(v1)
ran2.append(r1)
times.append(x)
x += 1
ax1.clear()
ax2.clear()
ax1.axes.set_ylim(min(ran1)-5, 5+max(ran1))
ax2.axes.set_ylim(min(ran2)-5, 5+max(ran2))
ax1.axes.set_xlim(x-200+200, x+20)
ax2.axes.set_xlim(x-200+20, x+20)
ax1.plot(times, ran1,'y')
ax2.plot(times, ran2,'r')
canvas.draw()
#global afterHandler
#afterHandler = root.after(10, drawImg)
#print(datetime.datetime.now())
def sub_task():
drawImg()
def task_(time):
def task__():
temp = BackgroundScheduler()
temp.add_job(sub_task,'interval',seconds = 1,end_date =str(datetime.datetime.now())[:17]+time)
temp.start()
return task__
sche_fn = BackgroundScheduler()
sche_fn.add_job(task_('25'),'cron',day_of_week = 'mon-fri',hour = '*',minute = '*',second = '0' )
sche_fn.start()
sche_an = BackgroundScheduler()
sche_an.add_job(task_('55'),'cron',day_of_week = 'mon-fri',hour = '*',minute = '*',second = '30' )
sche_an.start()
def on_closing():
sche_an.shutdown()
sche_fn.shutdown()
#root.after_cancel(afterHandler)
answer = messagebox.askokcancel("退出", "确定退出吗?")
if answer:
plt.close('all')
root.destroy()
else:
root.after(1000, drawImg)
root.protocol("WM_DELETE_WINDOW", on_closing)
root.mainloop()
1
shniubobo 2021-01-27 09:39:42 +08:00 via Android 1
如果要暂停函数的话可以考虑`yield`。函数里有`yield`的话,调用函数会返回一个生成器。`next(生成器)`会让函数运行到`yield`处中断,并返回`yield`的值,这样就相当于暂停了函数。有关`yield`见 python 文档语言参考部分,`next`见标准库参考部分。
还有就是考虑协程了,见标准库的`asyncio`。python 早期的协程其实也是基于上面说的生成器的。 |
2
yellowtail OP @shniubobo 感谢回复。
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