请教一个 docker 打包的问题

[vonsy]

Dockerfile

FROM nginx:latest
COPY ./default.conf /etc/nginx/conf.d/default.conf

default.conf:

location / {
root /usr/share/nginx/html;
index index.html index.htm;
deny all;
}

docker build -t nginx:20220426 .

为什么 CMD ["nginx" "-g" "daemon off;"]在前, COPY ./default.conf /etc/nginx/conf.d/default.conf 在后, 但配置中的 deny all; 依然生效. 谢谢

[GopherDaily]

https://docs.docker.com/engine/reference/builder/#cmd

There can only be one CMD instruction in a Dockerfile. If you list more than one CMD then only the last CMD will take effect.

The main purpose of a CMD is to provide defaults for an executing container. These defaults can include an executable, or they can omit the executable, in which case you must specify an ENTRYPOINT instruction as well.

类似 Python 的变量声明，语句可以应用语句之后声明的变量，因为编译时会统一把变量声明提到前面去

[ch2]

CMD 表示的是 docker run 或者 start 运行时执行的命令，在构建的时候放在哪无任何区别

[wd]

你没弄明白 build 和 run 的区别...

[vonsy]

@GopherDaily
@ch2
明白了,谢谢.

https://stackoverflow.com/questions/21553353/what-is-the-difference-between-cmd-and-entrypoint-in-a-dockerfile